33x^2+50x+8=0

Solution for 33x^2+50x+8=0 equation:

33x^2+50x+8=0

a = 33; b = 50; c = +8;
Δ = b2-4ac
Δ = 502-4·33·8
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-38}{2*33}=\frac{-88}{66}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+38}{2*33}=\frac{-12}{66}
=-2/11
$